я следующий MySQL Queryподзапросов в регистрации в CodeIgnitier
SELECT
events.id AS id,
A.sold_tickets
FROM (`events`)
JOIN `category` AS cat
ON `events`.`category_id` = `cat`.`id`
JOIN `category` AS sub_cat
ON `events`.`subCategoryID` = `sub_cat`.`id`
JOIN `events_custom_dates` AS events_date
ON `events_date`.`event_id` = `events`.`id`
JOIN `my_promos`
ON `events`.id = `my_promos`.`event_id`
LEFT JOIN `mycalendar`
ON `mycalendar`.`event_id` = `my_promos`.`event_id`
LEFT JOIN `promo_events_stats`
ON `promo_events_stats`.`id` = `events`.`id`
LEFT JOIN (SELECT
my_promos.event_id,
SUM(tickets_sold.quantity) AS sold_tickets
FROM my_promos
JOIN tickets_sold
ON tickets_sold.code = my_promos.link_code
WHERE my_promos.user_id = '532'
AND DATE(my_promos.date) >= '2013-11-01'
AND DATE(my_promos.date) <= '2014-01-22'
GROUP BY my_promos.event_id) A
ON A.event_id = events.id
WHERE `my_promos`.`user_id` = '532'
AND DATE(my_promos.date) >= '2013-11-01'
AND DATE(my_promos.date) <= '2014-01-22'
GROUP BY my_promos.event_id
я хочу, чтобы преобразовать часть, содержащую подзапрос в codeignitier образом присоединиться. что следующая
LEFT JOIN (SELECT
my_promos.event_id,
SUM(tickets_sold.quantity) AS sold_tickets
FROM my_promos
JOIN tickets_sold
ON tickets_sold.code = my_promos.link_code
WHERE my_promos.user_id = '532'
AND DATE(my_promos.date) >= '2013-11-01'
AND DATE(my_promos.date) <= '2014-01-22'
GROUP BY my_promos.event_id) A
ON A.event_id = events.id
я хочу это выше в структуре запросов codeignitier
[Здесь] (http://stackoverflow.com/questions/11023318/using-mysql-where-in-clause-in-codeigniter/11031431#11031431) является ответом –