Oracle Sql Query: Как функция функции Pivot() в пакетах?

Question

Я использую Oracle 10g и запрос в пакетах. Как функция Pivot sum() в пакетах?

Sql Query.

WITH DATA_JOIN AS 
(SELECT S.START_DATE_GMT, 
     S.NO_OF_CALL, 
     S.RATE, 
     T.TAX_RATE, 
     T.EFF_DATE, 
     T.EXP_DATE, 
     S.COMPANY_CODE, 
     T.COMPANY_CODE CC, 
     S.SUB_EVENT_TYPE_ID, 
     S.event_type_id, 
     S.PMN_ORIGIN, 
     S.PMN_ROUTE 
    FROM IR_V_ISM_RATE_BY_TRANS S 
    LEFT JOIN IR_PMN_TAX T 
     ON S.COMPANY_CODE = T.COMPANY_CODE 
    AND S.PMN_ROUTE = T.PMN_CODE 
    WHERE T.TAX_TYPE = '01' 
    AND S.START_DATE_GMT <= T.EFF_DATE 
    AND S.START_DATE_GMT >= T.EXP_DATE 
     OR T.EXP_DATE IS NULL 
    ORDER BY COMPANY_CODE), 
TEMP_A AS 
(SELECT START_DATE_GMT, 
     SUM(NO_OF_CALL) AS TOTAL_TRANSACTION, 
     ((SUM(NO_OF_CALL)) * RATE) AS TOTAL_AMOUNT, 
     ((((SUM(NO_OF_CALL)) * RATE) * TAX_RATE)/100) AS TOTAL_VAT, 
     RATE 
    FROM DATA_JOIN 
    WHERE COMPANY_CODE = 'RIT' 
    AND SUB_EVENT_TYPE_ID = '2' 
    AND PMN_ROUTE = 'C2' 
    AND EVENT_TYPE_ID = '01' 
    AND TO_CHAR(START_DATE_GMT, 'MM/YYYY') <= '01/2015' 
    AND (TO_CHAR(START_DATE_GMT, 'MM/YYYY') >= '01/2015' OR START_DATE_GMT IS NULL) 
    GROUP BY START_DATE_GMT, SUB_EVENT_TYPE_ID, RATE, TAX_RATE 
    ORDER BY START_DATE_GMT) 

/* Result */ 
SELECT 
SUM(TOTAL_AMOUNT)AS EXCLUDE_VAT, 
SUM(TOTAL_VAT) AS SUM_VAT, 
SUM(SUM(TOTAL_AMOUNT)+SUM(TOTAL_VAT)) AS TOTAL_INCLUDE 
FROM TEMP_A 
GROUP BY TOTAL_AMOUNT,TOTAL_VAT; 

Результат SQL Query

EXCLUDE_VAT | SUM_VAT | TOTAL_INCLUDE 
5.50  | 0.30 | 5.80 

мне нужно Результат Pivot

Calculate Vat | Total Amount 
---------------------------------- 
EXCLUDE_VAT  | 5.50 
SUM_VAT   | 0.30 
TOTAL_INCLUDE | 5.80 

Как Pivot Функция Sum() в пакетах?

Answer 1

Вам необходимо развернуть, а не поворот, но 10g не поддерживает ни изначально. Есть способы сделать это, as shown here with decode, но в этом случае, так как у вас уже есть КТР вы можете просто накидные три запроса против тех, кто вместо того, чтобы:

/* Result */ 
SELECT 'EXCLUDE_VAT' AS CALCULATE_VAT, 
    SUM(TOTAL_AMOUNT) AS TOTAL_AMOUNT 
FROM TEMP_A 
UNION ALL 
SELECT 'TOTAL_VAT', SUM(TOTAL_VAT) 
FROM TEMP_A 
UNION ALL 
SELECT 'TOTAL_INCLUDE', SUM(TOTAL_AMOUNT)+SUM(TOTAL_VAT) 
FROM TEMP_A; 

Answer 2

У меня нет доступа к Oracle db прямо сейчас, однако я помню, что существуют ограничения на использование PIVOT с операторами WITH. Я мог ошибаться.

select * from (
    select 1 AS CV_ORDER, 
     'EXCLUDE_VAT' as CALCULATE_VAT, 
     SUM(TOTAL_AMOUNT) as TOTAL_AMOUNT 
    from TEMP_A group by 1, 'EXCLUDE_VAT' 
    union all 
    select 2 as CV_ORDER, 
     'SUM_VAT' as CALCULATE_VAT, 
     SUM(TOTAL_VAT) as TOTAL_AMOUNT 
    from TEMP_A group by 2, 'SUM_VAT' 
    union all 
    select 3 as CV_ORDER, 
     'TOTAL_INCLUDE' as CALCULATE_VAT, 
     SUM(TOTAL_AMOUNT) + SUM)(TOTAL_VAT) as TOTAL_AMOUNT 
     from TEMP_A group by 3, 'TOTAL_INCLUDE' 
    ) order by CV_ORDER