Как сохранить отрицательные числа на языке ассемблера TASM? x86

Question

; У меня есть эта проблема, и я должен решить ее с указанными числами, кто-нибудь поможет !!! ; 13. (a + b + c * d)/(9-a) ; a, c, d-байт; б-двойное

ASSUME cs:code, 

ds:data 

DATA SEGMENT 
a db 11 
b dd 1 
c db -2 
d db 2 

res1 dw ? 
finalres dw ? 

data ends 

code segment 

start: 

mov ax, data 
mov ds, ax 

mov al, a 
cbw 
mov bl,9 
cbw 
sub bx,ax 
mov res1, ax 

mov al, c 
cbw 
mul d 
mov cl,a 
cbw 
add ax,cx 

mov bx, word ptr b 
mov cx, word ptr b+2 
add bx, ax 
adc cx, dx 
mov ax, bx 
mov dx ,cx 
mov cx, res1 
cwd 
div res1 
mov finalres, ax 

mov ax, 4C00h 
int 21h 

code ends 

end start 

Answer 1

Ваш код содержит несколько ошибок:

mov al, a 
cbw 
mov bl,9 
    ## This cbw will do a conversion AL -> AX 
    ## cbw/cwd instructions always influence the AX 
    ## register. It is not possible to use cbw for 
    ## the BX register! 
    ## 
    ## BTW: The value of the BH part of the BX 
    ## register is undefined here! 
cbw 
sub bx,ax 
mov res1, ax 
mov al, c 
cbw 
    ## Mul is an unsigned multiplication! 
    ## Imul would do a signed one! 
mul d 
mov cl,a 
    ## Again you try to use cbw for another register 
    ## than AX -> This will only destroy the AX 
    ## register! 
cbw 
add ax,cx 
    ## Because the "add ax,cx" may generate a carry 
    ## you'll have to do an "adc dx, 0" here! 
mov bx, word ptr b 
mov cx, word ptr b+2 
add bx, ax 
adc cx, dx 
    ## Why didn't you do an "add ax, bx" and an 
    ## "adc dx, cx" - you would not need the next 
    ## two instructions in this case? 
    ## (However this is not a real error.) 
mov ax, bx 
mov dx, cx 
    ## This instruction is useless 
    ## unless you use "(i)div cx" below! 
mov cx, res1 
    ## Why do you do this "cwd" here? 
    ## The high 16 bits of the 32-bit word "b" 
    ## will get lost when doing so! 
    ## 
    ## All operations on the "dx" register above 
    ## are also useless when doing this here! 
cwd 
    ## "div" will do an unsigned division. For a 
    ## signed division use "idiv" 
div res1 
mov finalres, ax 

Я не уверен, если я нашел все ошибки в коде.