Имея простую форму для загрузки изображения, я хочу отображать изображение после загрузки. Все работает отлично, файл также загружается, но фотография не отображается. Пожалуйста, помогите. форма:Отображение изображения после загрузки
<form name="newad" method="post" enctype="multipart/form-data" action="doctor.php">
<input type="file" name="image">
<input name="Submit" type="submit" value="Upload image">
</form>
И PHP:
<?php
//define a maxim size for the uploaded images in Kb
define ("MAX_SIZE","5060");
//This function reads the extension of the file. It is used to determine if the file is an image by checking the extension.
function getExtension($str)
{
$i = strrpos($str,".");
if (!$i) { return ""; }
$l = strlen($str) - $i;
$ext = substr($str,$i+1,$l);
return $ext;
}
//This variable is used as a flag. The value is initialized with 0 (meaning no error found)
//and it will be changed to 1 if an errro occures.
//If the error occures the file will not be uploaded.
$errors=0;
//checks if the form has been submitted
if(isset($_POST['Submit']))
{
//reads the name of the file the user submitted for uploading
$image=$_FILES['image']['name'];
//if it is not empty
if ($image)
{
//get the original name of the file from the clients machine
$filename = stripslashes($_FILES['image']['name']);
//get the extension of the file in a lower case format
$extension = getExtension($filename);
$extension = strtolower($extension);
/*if it is not a known extension, we will suppose it is an error
and will not upload the file, otherwise we will do more tests */
if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif"))
{
//print error message
echo '<h2>Unknown extension!</h2>';
$errors=1;
}
else
{
//get the size of the image in bytes
//$_FILES['image']['tmp_name'] is the temporary filename of the file
//in which the uploaded file was stored on the server
$size=filesize($_FILES['image']['tmp_name']);
//compare the size with the maxim size we defined and print error if bigger
if ($size > MAX_SIZE*1024)
{
echo '<h2>You have exceeded the file size limit! Please reduce the image size to 100 Kb or less!</h2>';
$errors=1;
}
//we will give an unique name, for example the time in unix time format
$image_name=$filename;
//the new name will be containing the full path where will be stored (images folder)
$newname="../images/".$image_name;
//we verify if the image has been uploaded, and print error instead
$copied = copy($_FILES['image']['tmp_name'], $newname);
if (!$copied)
{
echo '<h2>Copy unsuccessful!</h2>';
$errors=1;
}
}
}
}
//If no errors registred, print the success message
if(isset($_POST['Submit']) && !$errors)
{
<img src="http://localhost/images/<?php echo $image_name; ?>" alt="There ya go" />
}
?>
Проблема ошибки я получаю:
Parse error: syntax error, unexpected '<' in C:\xampp\htdocs\alka.php on line 65
Использование открытие эхо => '
первую ошибку я вижу donald123