Как работать рок, бумага, ножницы игра в Python

Question

Я пытаюсь сделать программу python для скалы, бумаги, ножниц, но я не могу заставить ее работать. Кто-нибудь может мне помочь? PS: Я использую Python 3.5

Я начинаю импортировать random и говорить Python запускать различные программы в зависимости от результата от random.randint(1,3)

import random 

def rps(): 
    computer_choice = random.randint(1,3) 
    if computer_choice == 1: 
     computer_choice_rock() 
    elif computer_choice == 2: 
     computer_choice_paper() 
    elif computer_choice == 3: 
     computer_choice_scissors() 

Я делаю программу он должен работать под этим текстом. Я думаю, что это может быть источником ошибок.

def computer_choice_rock(): 
    use_choice = raw_input("1 for Rock, 2 for paper, 3 for Scissors: ") 
    if user_choice == "1": 
     print ("You Tie. You chose Rock, and the computer chose Rock.") 
     try_again() 
    if user_choice == "2": 
     print ("you win. You chose Paper, and the computer chose Rock.") 
     try_again() 
    if user_choice == "3": 
     print ("you lose. You chose Scissors, and the computer chose Rock.") 
     try_again() 
    else: 
     print ("try again") 
     computer_choice_rock() 

def computer_choice_paper(): 
    use_choice = raw_input("1 for Rock, 2 for paper, 3 for Scissors: ") 
    if user_choice == "1": 
     print ("you lose. You chose Rock, and the computer chose Paper.") 
     try_again() 
    if user_choice == "2": 
     print ("you tie. You chose Paper, and the computer chose Paper.") 
     try_again() 
    if user_choice == "3": 
     print ("you win. You chose Scissors, and the computer chose Paper.") 
     try_again() 
    else: 
     print ("try again") 
     computer_choice_paper() 

def computer_choice_scissors(): 
    use_choice = raw_input("1 for Rock, 2 for paper, 3 for Scissors: ") 
    if user_choice == "1": 
     print ("you win. You chose Rock, and the computer chose Scissors.") 
     try_again() 
    if user_choice == "2": 
     print ("you lose. You chose Paper, and the computer chose Scissors.") 
     try_again() 
    if user_choice == "3": 
     print ("you tie. You chose Scissors, and the computer chose Scissors.") 
     try_again() 
    else: 
     print ("try again") 
     computer_choice_rock() 


def try_again(): 
    choice = raw_input("Would you like to play again? y/n ") 
    if choice == "y" or choice == "yes" or choice =="Y" or choice == "Yes": 
     rps() 
    elif choice == "n": 
     print ("Thanks for playing") 
     quit() 
    else: 
     print ("Try again") 
     try_again() 
rps() 

Сообщение об ошибке:

Traceback (most recent call last): 
    File "C:/Users/Jakob/Desktop/rps.py", line 68, in <module> 
    rps() 
    File "C:/Users/Jakob/Desktop/rps.py", line 8, in rps 
    computer_choice_paper() 
    File "C:/Users/Jakob/Desktop/rps.py", line 28, in computer_choice_paper 
    user_choice = raw_input("1 for Rock, 2 for paper, 3 for Scissors: ") 
NameError: name 'raw_input' is not defined 

Answer 1

Вы принимаете raw_input, как use_choice и сравнение user_choice. Имена переменных разные.