конвертирование $ .each в собственный javascript - лучший подход

Question

У меня есть такой код, который я хочу преобразовать в родной JavaScript. Каков наилучший подход?

$.each(data.results, function (i, val) { 
    var venueObj = val.venue; 
    if ((venueObj && venueObj.lat != 0)) { 
     meetupName.push(val.name); 
     meetupDescript.push(val.description); 
     meetupUrl.push(val.event_url); 

     //meetupLat = []; 
     meetupLat.push(venueObj['lat']); 
     //meetupLong = []; 
     meetupLon.push(venueObj['lon']); 

     //address 
     meetupAddress.push(venueObj['address_1'] + "</h3><h3>" + venueObj['city']); 
    } else { 
     return; 
    }  
}); 

Answer 1

Вы должны опустить "возвращение" в цикле

for(var i in data.results) { 
    var val = data.results[i] 
    var venueObj = val.venue; 
    if ((venueObj && venueObj.lat != 0)) { 
     meetupName.push(val.name); 
     meetupDescript.push(val.description); 
     meetupUrl.push(val.event_url); 

     //meetupLat = []; 
     meetupLat.push(venueObj['lat']); 
     //meetupLong = []; 
     meetupLon.push(venueObj['lon']); 

     //address 
     meetupAddress.push(venueObj['address_1'] + "</h3><h3>" + venueObj['city']); 
    }  
}