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Я делаю регистрационную форму на PHP и при отправке формы Date (Check In, для которой я использовал Date Picker), Combo boxes (Sex & Room No) & флажок (такси) не вставлен.Значения даты и поля со списком не собираются в mysql
Я достаточно посмотрел на код, но не понял, что не так. Хотя другие поля со списком и флажок работают нормально.
PHP код -
<?php
$passport = $_POST['passport'];
$name = $_POST['name'];
$sex = $_POST['sex'];
$address1 = $_POST['address1'];
$address2 = $_POST['address2'];
$city = $_POST['city'];
$country = $_POST['country'];
$contact = $_POST['contact'];
$email = $_POST['email'];
$roomNo = $_POST['roomNo'];
if(isset($_POST['food']) && $_POST['food'] == 'food')
{
$food = 'yes';
}
else
{
$food = 'no';
}
if(isset($_POST['car']) && $_POST['car'] == 'car')
{
$car = 'yes';
}
else
{
$car = 'no';
}
if(isset($_POST['others']) && $_POST['others'] == 'others')
{
$others = 'yes';
}
else
{
$others = 'no';
}
$checkIn = $_POST['checkIn'];
mysql_connect("localhost","root","");
mysql_select_db("guesthouse");
$personal_query = "INSERT INTO personal_details VALUES(
'',
'$name',
'$sex',
'$address1',
'$address2',
'$city',
'$country',
'$contact',
'$email')";
mysql_query($personal_query);
$result = mysql_affected_rows();
if($result == 1)
{
echo "Personal Details Submitted";
}
$booking_query = "INSERT INTO booking VALUES(
'',
'$name',
'$roomno',
'$food',
'$taxi',
'$others',
'$checkIn')";
mysql_query($booking_query);
$result = mysql_affected_rows();
if($result == 1) {
echo "<br/>Booking Details Submitted";
}
?>
HTML -
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<link rel="stylesheet" type="text/css" media="all" href="jsDatePick_ltr.min.css" />
<script type="text/javascript" src="jsDatePick.min.1.3.js"></script>
<script type="text/javascript">
window.onload = function(){
new JsDatePick({
useMode:2,
target:"checkIn",
dateFormat:"%d-%M-%Y"
/*selectedDate:{
day:5,
month:9,
year:2006
},
yearsRange:[1978,2020],
limitToToday:false,
cellColorScheme:"beige",
dateFormat:"%m-%d-%Y",
imgPath:"img/",
weekStartDay:1*/
});
};
</script>
</head>
<form name="form1" method="post" action="registration_handle.php">
<table width="60%" border="0" align="center" cellpadding="0" cellspacing="0">
<tr>
<td colspan="2" align="center" bgcolor="#0099FF">Room Reservation Details :</td>
</tr>
<tr>
<td width="33%" align="center" bgcolor="#66FFCC">Passport No </td>
<td width="67%"><label for="textfield"></label>
<input type="text" name="passport" id="passport"></td>
</tr>
<tr>
<td align="center" bgcolor="#66FFCC">Name</td>
<td><input type="text" name="name" id="name"></td>
</tr>
<tr>
<td align="center" bgcolor="#66FFCC">Sex</td>
<td><label for="select3"></label>
<select name="sex" id="sex">
<option value="" selected>Male</option>
<option value="" >Female</option>
</select></td>
</tr>
<tr>
<td align="center" bgcolor="#66FFCC">Address 1</td>
<td><input type="text" name="address1" id="address1"></td>
</tr>
<tr>
<td align="center" bgcolor="#66FFCC">Address2</td>
<td><input type="text" name="address2" id="address2"></td>
</tr>
<tr>
<td align="center" bgcolor="#66FFCC">City</td>
<td><input type="text" name="city" id="city" /></td>
</tr>
<tr>
<td align="center" bgcolor="#66FFCC">Country</td>
<td><label for="select2"></label>
<select name="country" id="country">
<?php
mysql_connect("localhost","root","");
mysql_select_db("guesthouse");
$query = "SELECT name FROM country";
$query_result = mysql_query($query);
while($result = mysql_fetch_assoc($query_result))
{
?>
<option value = "<?php echo $result['name'] ?>"><?php echo $result['name'] ?></option>
<?php
}
?>
</select></td>
</tr>
<tr>
<td align="center" bgcolor="#66FFCC">Contact No</td>
<td><input type="text" name="contact" id="contact"></td>
</tr>
<tr>
<td align="center" bgcolor="#66FFCC">E-Mail </td>
<td><input type="text" name="email" id="email"></td>
</tr>
<tr>
<td> </td>
<td> </td>
</tr>
<tr>
<td align="center" bgcolor="#66FFCC">Room No</td>
<td><label for="select4"></label>
<select name="roomNo" id="roomNo">
<?php
mysql_connect("localhost","root","");
mysql_select_db("guesthouse");
$query = "SELECT name FROM roomno";
$query_result = mysql_query($query);
while($result = mysql_fetch_assoc($query_result))
{
?>
<option value = "<?php echo $result['name'] ?>"><?php echo $result['name'] ?></option>
<?php
}
?>
</select></td>
</tr>
<tr>
<td align="center" bgcolor="#66FFCC">Extra Service</td>
<td><p>
<label> </label>
<input type="checkbox" name="food" value="food" />Food
<input type="checkbox" name="car" value="car" />Car
<input type="checkbox" name="others" value="others" />Others<br>
</p></td>
</tr>
<tr>
<td align="center" bgcolor="#66FFCC">Check In </td>
<td><label for="textfield3"></label>
<input type="text" size="16" name="checkIn" id="checkIn"></td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="button" id="button" value="Submit">
<input type="reset" name="Reset" id="Reset" value="Reset" />
<input type="submit" name="cancel" id="cancel" value="Cancel" /></td>
</tr>
</table>
</form>
</html>
вам нужно указать поля вставки/строки вставить проверить INSERT: http: // dev .mysql.com/doc/refman/5.0/en/insert.html –
Когда мы отправляем каждое значение для любой таблицы, нам не нужно описывать имя полей таблицы. Другие значения полей вставляются, но только некоторые заданные значения полей NULL –
Можете ли вы разместить HTML? – j08691