Выберите размер базы данных SQL Server

Question

как я могу запросить мой сервер sql только для получения размера базы данных?

Я использовал это:

use "MY_DB" 
exec sp_spaceused 

Я получил это:

database_name database_size unallocated space 
My_DB   17899.13 MB 5309.39 MB 

Он возвращает мне несколько столбца, который я не нужен, может быть, есть трюк, чтобы выбрать database_size столбца из этих хранимых процедура ?

Я также попробовал этот код:

SELECT DB_NAME(database_id) AS DatabaseName, 
     Name AS Logical_Name, 
     Physical_Name, 
     (size * 8)/1024 SizeMB 
FROM sys.master_files 
WHERE DB_NAME(database_id) = 'MY_DB' 

Это дает мне этот результат:

DatabaseName Logical_Name Physical_Name     SizeMB 
MY_DB   MY_DB   D:\MSSQL\Data\MY_DB.mdf   10613 
MY_DB   MY_DB_log  D:\MSSQL\Data\MY_DB.ldf   7286 

Так я написал это:

SELECT SUM(SizeMB) 
FROM (
    SELECT DB_NAME(database_id) AS DatabaseName, 
      Name AS Logical_Name, 
      Physical_Name, 
      (size * 8)/1024 SizeMB 
    FROM sys.master_files 
    WHERE DB_NAME(database_id) = 'MY_DB' 
) AS TEMP 

я получил: 1183

Так оно работает, но, может быть, там это правильный способ получить это?

Answer 1

Попробуйте один -

Запрос:

SELECT 
     database_name = DB_NAME(database_id) 
    , log_size_mb = CAST(SUM(CASE WHEN type_desc = 'LOG' THEN size END) * 8./1024 AS DECIMAL(8,2)) 
    , row_size_mb = CAST(SUM(CASE WHEN type_desc = 'ROWS' THEN size END) * 8./1024 AS DECIMAL(8,2)) 
    , total_size_mb = CAST(SUM(size) * 8./1024 AS DECIMAL(8,2)) 
FROM sys.master_files WITH(NOWAIT) 
WHERE database_id = DB_ID() -- for current db 
GROUP BY database_id 

Выход:

-- my query 
name   log_size_mb row_size_mb total_size_mb 
-------------- ------------ ------------- ------------- 
xxxxxxxxxxx 512.00  302.81  814.81 

-- sp_spaceused 
database_name database_size  unallocated space 
---------------- ------------------ ------------------ 
xxxxxxxxxxx  814.81 MB   13.04 MB 

Функция:

ALTER FUNCTION [dbo].[GetDBSize] 
(
    @db_name NVARCHAR(100) 
) 
RETURNS TABLE 
AS 
RETURN 

    SELECT 
     database_name = DB_NAME(database_id) 
     , log_size_mb = CAST(SUM(CASE WHEN type_desc = 'LOG' THEN size END) * 8./1024 AS DECIMAL(8,2)) 
     , row_size_mb = CAST(SUM(CASE WHEN type_desc = 'ROWS' THEN size END) * 8./1024 AS DECIMAL(8,2)) 
     , total_size_mb = CAST(SUM(size) * 8./1024 AS DECIMAL(8,2)) 
    FROM sys.master_files WITH(NOWAIT) 
    WHERE database_id = DB_ID(@db_name) 
     OR @db_name IS NULL 
    GROUP BY database_id 

UPDATE 2016/01/22:

Показать информацию о размере, свободном пространстве, последней копии базы данных

IF OBJECT_ID('tempdb.dbo.#space') IS NOT NULL 
    DROP TABLE #space 

CREATE TABLE #space (
     database_id INT PRIMARY KEY 
    , data_used_size DECIMAL(18,2) 
    , log_used_size DECIMAL(18,2) 
) 

DECLARE @SQL NVARCHAR(MAX) 

SELECT @SQL = STUFF((
    SELECT ' 
    USE [' + d.name + '] 
    INSERT INTO #space (database_id, data_used_size, log_used_size) 
    SELECT 
      DB_ID() 
     , SUM(CASE WHEN [type] = 0 THEN space_used END) 
     , SUM(CASE WHEN [type] = 1 THEN space_used END) 
    FROM (
     SELECT s.[type], space_used = SUM(FILEPROPERTY(s.name, ''SpaceUsed'') * 8./1024) 
     FROM sys.database_files s 
     GROUP BY s.[type] 
    ) t;' 
    FROM sys.databases d 
    WHERE d.[state] = 0 
    FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 2, '') 

EXEC sys.sp_executesql @SQL 

SELECT 
     d.database_id 
    , d.name 
    , d.state_desc 
    , d.recovery_model_desc 
    , t.total_size 
    , t.data_size 
    , s.data_used_size 
    , t.log_size 
    , s.log_used_size 
    , bu.full_last_date 
    , bu.full_size 
    , bu.log_last_date 
    , bu.log_size 
FROM (
    SELECT 
      database_id 
     , log_size = CAST(SUM(CASE WHEN [type] = 1 THEN size END) * 8./1024 AS DECIMAL(18,2)) 
     , data_size = CAST(SUM(CASE WHEN [type] = 0 THEN size END) * 8./1024 AS DECIMAL(18,2)) 
     , total_size = CAST(SUM(size) * 8./1024 AS DECIMAL(18,2)) 
    FROM sys.master_files 
    GROUP BY database_id 
) t 
JOIN sys.databases d ON d.database_id = t.database_id 
LEFT JOIN #space s ON d.database_id = s.database_id 
LEFT JOIN (
    SELECT 
      database_name 
     , full_last_date = MAX(CASE WHEN [type] = 'D' THEN backup_finish_date END) 
     , full_size = MAX(CASE WHEN [type] = 'D' THEN backup_size END) 
     , log_last_date = MAX(CASE WHEN [type] = 'L' THEN backup_finish_date END) 
     , log_size = MAX(CASE WHEN [type] = 'L' THEN backup_size END) 
    FROM (
     SELECT 
       s.database_name 
      , s.[type] 
      , s.backup_finish_date 
      , backup_size = 
         CAST(CASE WHEN s.backup_size = s.compressed_backup_size 
            THEN s.backup_size 
            ELSE s.compressed_backup_size 
         END/1048576.0 AS DECIMAL(18,2)) 
      , RowNum = ROW_NUMBER() OVER (PARTITION BY s.database_name, s.[type] ORDER BY s.backup_finish_date DESC) 
     FROM msdb.dbo.backupset s 
     WHERE s.[type] IN ('D', 'L') 
    ) f 
    WHERE f.RowNum = 1 
    GROUP BY f.database_name 
) bu ON d.name = bu.database_name 
ORDER BY t.total_size DESC 

Выход:

database_id name        state_desc recovery_model_desc total_size data_size data_used_size log_size log_used_size full_last_date   full_size log_last_date   log_size 
----------- -------------------------------- ------------ ------------------- ------------ ----------- --------------- ----------- -------------- ----------------------- ------------ ----------------------- --------- 
24   StackOverflow     ONLINE  SIMPLE    66339.88  65840.00 65102.06  499.88  5.05   NULL     NULL   NULL     NULL 
11   AdventureWorks2012    ONLINE  SIMPLE    16404.13  15213.00 192.69   1191.13  15.55   2015-11-10 10:51:02.000 44.59  NULL     NULL 
10   locateme       ONLINE  SIMPLE    1050.13  591.00  2.94   459.13  6.91   2015-11-06 15:08:34.000 17.25  NULL     NULL 
8   CL_Documents      ONLINE  FULL    793.13  334.00  333.69   459.13  12.95   2015-11-06 15:08:31.000 309.22  2015-11-06 13:15:39.000 0.01 
1   master       ONLINE  SIMPLE    554.00  492.06  4.31   61.94  5.20   2015-11-06 15:08:12.000 0.65   NULL     NULL 
9   Refactoring      ONLINE  SIMPLE    494.32  366.44  308.88   127.88  34.96   2016-01-05 18:59:10.000 37.53  NULL     NULL 
3   model       ONLINE  SIMPLE    349.06  4.06  2.56   345.00  0.97   2015-11-06 15:08:12.000 0.45   NULL     NULL 
13   sql-format.com     ONLINE  SIMPLE    216.81  181.38  149.00   35.44  3.06   2015-11-06 15:08:39.000 23.64  NULL     NULL 
23   users       ONLINE  FULL    173.25  73.25  3.25   100.00  5.66   2015-11-23 13:15:45.000 0.72   NULL     NULL 
4   msdb        ONLINE  SIMPLE    46.44  20.25  19.31   26.19  4.09   2015-11-06 15:08:12.000 2.96   NULL     NULL 
21   SSISDB       ONLINE  FULL    45.06  40.00  4.06   5.06  4.84   2014-05-14 18:27:11.000 3.08   NULL     NULL 
27   tSQLt       ONLINE  SIMPLE    9.00   5.00  3.06   4.00  0.75   NULL     NULL   NULL     NULL 
2   tempdb       ONLINE  SIMPLE    8.50   8.00  4.50   0.50  1.78   NULL     NULL   NULL     NULL 

Answer 2

сравнить также результаты с результатом следующего запроса

EXEC sp_helpdb @dbname= 'MSDB' 

Это дает результат, аналогичный следующему

Существует хорошая статья - Different ways to determine free space for SQL Server databases and database files

Answer 3

ВАС проверить, как этот запрос работает в ссылке ниже.

https://gallery.technet.microsoft.com/SIZE-OF-ALL-DATABASES-IN-0337f6d5/

IF OBJECT_ID('tempdb..#spacetable') IS NOT NULL 
DROP TABLE tempdb..#spacetable 
create table #spacetable 
(
database_name varchar(50) , 
total_size_data int, 
space_util_data int, 
space_data_left int, 
percent_fill_data float, 
total_size_data_log int, 
space_util_log int, 
space_log_left int, 
percent_fill_log char(50), 
[total db size] int, 
[total size used] int, 
[total size left] int 
) 
insert into #spacetable 
EXECUTE master.sys.sp_MSforeachdb 'USE [?]; 
select x.[DATABASE NAME],x.[total size data],x.[space util],x.[total size data]-x.[space util] [space left data], 
x.[percent fill],y.[total size log],y.[space util], 
y.[total size log]-y.[space util] [space left log],y.[percent fill], 
y.[total size log]+x.[total size data] ''total db size'' 
,x.[space util]+y.[space util] ''total size used'', 
(y.[total size log]+x.[total size data])-(y.[space util]+x.[space util]) ''total size left'' 
from (select DB_NAME() ''DATABASE NAME'', 
sum(size*8/1024) ''total size data'',sum(FILEPROPERTY(name,''SpaceUsed'')*8/1024) ''space util'' 
,case when sum(size*8/1024)=0 then ''divide by zero'' else 
substring(cast((sum(FILEPROPERTY(name,''SpaceUsed''))*1.0*100/sum(size)) as CHAR(50)),1,6) end ''percent fill'' 
from sys.master_files where database_id=DB_ID(DB_NAME()) and type=0 
group by type_desc ) as x , 
(select 
sum(size*8/1024) ''total size log'',sum(FILEPROPERTY(name,''SpaceUsed'')*8/1024) ''space util'' 
,case when sum(size*8/1024)=0 then ''divide by zero'' else 
substring(cast((sum(FILEPROPERTY(name,''SpaceUsed''))*1.0*100/sum(size)) as CHAR(50)),1,6) end ''percent fill'' 
from sys.master_files where database_id=DB_ID(DB_NAME()) and type=1 
group by type_desc )y' 
select * from #spacetable 
order by database_name 
drop table #spacetable 

Answer 4

работал отлично для меня, чтобы рассчитать размер базы данных SQL в SQL Server 2012

exec sp_spaceused 

Answer 5

Вы можете просто запустить следующее:

exec sp_spaceused

Он предоставит вам общее пространство, используемое для этой базы данных.

Answer 6

SELECT  sys.databases.name AS [Database Name], 
     CONVERT(VARCHAR,SUM(size)*8/1024)+' MB' AS [Size] 
    FROM  sys.databases 
    JOIN  sys.master_files 
    ON   sys.databases.database_id=sys.master_files.database_id 
    GROUP BY sys.databases.name 
    ORDER BY sys.databases.name