XSLT Группировка с SUM не работает, когда первый путь не имеет соответствующего элемента

Question

При выполнении суммы с группировкой и совпадающим узлом не существует в первом элементе этой группы, тогда результат будет пустым.

XML

<?xml version="1.0" encoding="UTF-8"?> 
<?xml-stylesheet type="text/xsl" href="EmployeeDetailStylesheet.xsl" ?> 
<PayDetailsExportResult xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> 
    <PayDetailExport> 
     <PayrollBatches> 
     <PayrollBatch> 

      <PayBatchEmployees> 
       <PayrollBatchEmployee> 
        <FirstName>Stacey</FirstName>     
        <NationalId>999999999</NationalId>     
        <PayrollBatchDetails> 
        <PayrollBatchDetail> 
         <DeductionAdjustmentsNotToInclude> 
          <DeductionAdjustment>        
           <TakenAmount>55.00</TakenAmount>        
           <DeductionType>401(k)</DeductionType>        
          </DeductionAdjustment> 
         </DeductionAdjustmentsNotToInclude> 
        </PayrollBatchDetail> 
        </PayrollBatchDetails> 
       </PayrollBatchEmployee> 
      </PayBatchEmployees> 

     </PayrollBatch> 

     <PayrollBatch>  

      <PayBatchEmployees> 
       <PayrollBatchEmployee> 
        <FirstName>Stacey</FirstName> 
        <NationalId>111111111</NationalId> 
        <PayrollBatchDetails> 
        <PayrollBatchDetail>       
         <DeductionAdjustmentss> 
          <DeductionAdjustment> 
           <TakenAmount>70.00</TakenAmount> 
           <DeductionType>401(k) - Catch up</DeductionType> 
          </DeductionAdjustment> 
         </DeductionAdjustmentss> 
        </PayrollBatchDetail> 
        <PayrollBatchDetail> 
         <DeductionAdjustments> 
          <DeductionAdjustment> 
           <TakenAmount>20.00</TakenAmount> 
           <DeductionType>401(k)</DeductionType> 
          </DeductionAdjustment> 
         </DeductionAdjustments> 
        </PayrollBatchDetail> 
        </PayrollBatchDetails> 
       </PayrollBatchEmployee> 
      </PayBatchEmployees> 
     </PayrollBatch> 

     </PayrollBatches> 
    </PayDetailExport> 
</PayDetailsExportResult> 

XSLT

<?xml version="1.0"?> 
<xsl:stylesheet version="1.0" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:pdi="http://www.profdata.com" 
       xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 

    <!-- strip-space removes whitespace nodes such as tabs and newlines that occur between elements.--> 
    <xsl:strip-space elements="*"/> 

    <!-- Set output method to indicate a text file (not XML) -->   
    <xsl:output method="text" encoding="utf-8" indent="yes"/> 

    <xsl:key name="payrollBatchEmpGroup" match="PayrollBatchEmployee" use="NationalId" /> 
    <xsl:key name="deductionAdjustmentGroup" match="DeductionAdjustments/DeductionAdjustment" use="concat(../../../../NationalId, '+', DeductionType)" /> 

    <xsl:template match="PayDetailsExportResult">    
     <!-- Output the CSV data row --> 
     <xsl:for-each select="PayDetailExport/PayrollBatches/PayrollBatch"> 

      <xsl:for-each select="PayBatchEmployees/PayrollBatchEmployee[count(. | key('payrollBatchEmpGroup', NationalId)[1]) = 1]"> 

       <xsl:variable name="ssn" select="NationalId" /> 
       <xsl:value-of select="FirstName"/> 
       <text>--</text> 

       <xsl:for-each select="PayrollBatchDetails/PayrollBatchDetail[DeductionAdjustments]">      

        <xsl:for-each select="DeductionAdjustments/DeductionAdjustment[DeductionType='401(k)'][count(. | key('deductionAdjustmentGroup', concat($ssn, '+', DeductionType))[1]) = 1]"> 
         <xsl:value-of select="sum(key('deductionAdjustmentGroup', concat($ssn , '+' , DeductionType))/TakenAmount)" />      
        </xsl:for-each> 

       </xsl:for-each> 

       <!--End of row-->   
       <xsl:text>&#xA;</xsl:text>      
      </xsl:for-each> 

     </xsl:for-each> 
    </xsl:template> 
</xsl:stylesheet> 

Результат

Stacey--

Ожидаемые результаты

Stacey-- 20

Примечание: - В тот момент мы изменяем узел DeductionAdjustmentsNotToInclude к DeductionAdjustments (означает первый элемент этой группы имеет соответствие узел) результат отображения правильно (т.е. - Стейси - 75).

Answer 1

Прежде всего, в вашем XML, вы должны исправить опечатку «DeductionAdjustmentss». Сделав это, это работает:

<?xml version="1.0"?> 
    <xsl:stylesheet version="1.0" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:pdi="http://www.profdata.com" 
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 

     <!-- strip-space removes whitespace nodes such as tabs and newlines that occur between elements.--> 
     <xsl:strip-space elements="*"/> 

     <!-- Set output method to indicate a text file (not XML) -->   
     <xsl:output method="text" encoding="utf-8" indent="yes"/> 

     <xsl:key name="payrollBatchEmpGroup" match="PayrollBatchEmployee" use="NationalId" /> 
     <xsl:key name="deductionAdjustmentGroup" match="DeductionAdjustments/DeductionAdjustment" use="concat(../../../../NationalId, '+', DeductionType)" /> 

     <xsl:template match="PayDetailsExportResult">    
      <!-- Output the CSV data row --> 
      <xsl:for-each select="PayDetailExport/PayrollBatches/PayrollBatch/PayBatchEmployees/PayrollBatchEmployee/PayrollBatchDetails/PayrollBatchDetail/DeductionAdjustments/DeductionAdjustment 
       [DeductionType='401(k)' and count(. | key('deductionAdjustmentGroup', concat(../../../../NationalId, '+', DeductionType))[1]) = 1]"> 
       <xsl:value-of select="key('payrollBatchEmpGroup', ../../../../NationalId)/FirstName"/> 
       <text>--</text> 
       <xsl:value-of select="sum(key('deductionAdjustmentGroup', concat(../../../../NationalId, '+' , DeductionType))/TakenAmount)" />   
       <!--End of row-->   
       <xsl:text>&#xA;</xsl:text>      
      </xsl:for-each> 
     </xsl:template> 
    </xsl:stylesheet>