Mysql ошибка - поставляется аргумент не является допустимым MySQL результаты ресурс

Question

мне нужна помощь с этой ошибкой:

Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in *****/log.php on line 15.

Вот строка 15: -

$query = "SELECT COUNT(id) AS amt FROM users WHERE name='$username' password='$password'"; 
$q = mysql_query($query,$c); 
$user = mysql_fetch_assoc($q); // line 15 
$amt_found = (int)$user['amt']; 

Answer 1

Вы упускаете И

$query = "SELECT COUNT(id) AS amt FROM users WHERE name='$username' AND password='$password'"; $q = mysql_query($query,$c); $user = mysql_fetch_assoc($q); // line 15 $amt_found = (int)$user['amt']; 

Answer 2

Вы забыли and

$query = "SELECT COUNT(id) AS amt FROM users 
WHERE name='$username' AND password='$password'"; 
         ^--------------------------here 

Answer 3

Вы пропустили AND здесь

изменение name='$username' password='$password'
в name='$username' AND password='$password'

$query = "SELECT COUNT(id) AS amt FROM users 
WHERE name='$username' AND password='$password'"; 

Answer 4

использование

$query = "SELECT COUNT(id) AS amt FROM users WHERE name='$username' AND password='$password'"; 
$q = mysql_query($query,$c); 
$user = mysql_fetch_assoc($q); // line 15 
$amt_found = (int)$user['amt'];