Wpf Treeview вопрос

Question

Как я показал бы ниже XML к WPF TreeView, и оно должно отображаться следующим образом

Категория Имя (Easy Puzzle)

• Головоломка Имя (# 1)

(Medium Puzzle)

• Puzzle Имя

  Категория Имя (# 1)

Категория Название (Hard Puzzle)

• Puzzle Имя (# 1)

XML

<?xml version="1.0"?> 
<SudokuLibrary xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> 
    <Puzzles> 
    <SudokuPuzzle> 
     <Category>Easy Puzzle</Category> 
     <Name>#1</Name> 
     <Rank>3</Rank> 
     <Format> 
     <string>6,0,0,5,0,4,7,0,0</string> 
     <string>4,9,5,0,0,8,3,6,0</string> 
     <string>1,0,7,0,0,0,0,0,0</string> 
     <string>0,5,0,0,0,1,4,2,8</string> 
     <string>0,0,0,2,0,9,0,0,0</string> 
     <string>3,2,1,8,0,0,0,5,0</string> 
     <string>0,0,0,0,0,0,5,0,3</string> 
     <string>0,1,3,6,0,0,8,7,4</string> 
     <string>0,0,8,1,0,3,0,0,2</string> 
     </Format> 
     <Solution> 
     <string>6,3,2,5,1,4,7,8,9</string> 
     <string>4,9,5,7,2,8,3,6,1</string> 
     <string>1,8,7,9,3,6,2,4,5</string> 
     <string>7,5,9,3,6,1,4,2,8</string> 
     <string>8,6,4,2,5,9,1,3,7</string> 
     <string>3,2,1,8,4,7,9,5,6</string> 
     <string>9,7,6,4,8,2,5,1,3</string> 
     <string>2,1,3,6,9,5,8,7,4</string> 
     <string>5,4,8,1,7,3,6,9,2</string> 
     </Solution> 
     <SaveState> 
     <string>6,0,0,5,0,4,7,0,0</string> 
     <string>4,9,5,0,0,8,3,6,0</string> 
     <string>1,0,7,0,0,0,0,0,0</string> 
     <string>0,5,0,0,0,1,4,2,8</string> 
     <string>0,0,0,2,0,9,0,0,0</string> 
     <string>3,2,1,8,0,0,0,5,0</string> 
     <string>0,0,0,0,0,0,5,0,3</string> 
     <string>0,1,3,6,0,0,8,7,4</string> 
     <string>0,0,8,1,0,3,0,0,2</string> 
     </SaveState> 
    </SudokuPuzzle> 
    <SudokuPuzzle> 
    **...** 
    </SudokuPuzzle> 
    </Puzzles> 
</SudokuLibrary> 

Я попытался следующие ниже

<ResourceDictionary> 
<XmlDataProvider x:Key="xmldata" Source="Data/SudokuLibrary.xml" XPath="/SudokuLibrary/Puzzles/SudokuPuzzle" /> 
      <HierarchicalDataTemplate x:Key="xmldatatemplate" ItemsSource="{Binding}"> 
       <TextBlock Margin="0" Text="{Binding XPath=Name}" /> 
      </HierarchicalDataTemplate> 
</ResourceDictionary> 

TreeView

<Grid DataContext="{StaticResource xmldata}"> 
<Grid.RowDefinitions> 
    <RowDefinition Height="*" /> 
    <RowDefinition Height="Auto" /> 
</Grid.RowDefinitions> 
<TreeView 
    x:Name="PuzzleTreeView" 
    Grid.Row="0" 
    Width="140" 
    Padding="3" 
    Margin="10" 
    ItemsSource="{Binding}" 
    SelectedItemChanged="PuzzleTreeView_SelectedItemChanged"/> 

Answer 1

Попробуйте это ..

public class PuzzleName 
    { 
    public String Name { get; set; } 
    public string puzzle{ get; set; } 

     } 

public class Puzzle 
{ 

public String CategoryName { get; set; } 
public List<PuzzleName> Children { get; set; } 

     public Puzzle(string Categoryname) 
     { 
      Children = new List<PuzzleName>(); 
     CategoryName= Categoryname; 
     } 
//read the xml file and create an object for the puzzle and load the puzzle name (#1) as its childern 
} 

В MVVM ...

List<Puzzle> puzzleList = new List<Puzzle> 

В видовом ...

<TreeView 
    x:Name="PuzzleTreeView" 
    Grid.Row="0" 
    Width="140" 
    Padding="3" 
    Margin="10" 
    ItemsSource="{Binding puzzleList , Mode=TwoWay,UpdateSourceTrigger=PropertyChanged}" 
    SelectedItemChanged="PuzzleTreeView_SelectedItemChanged"/>