Нужна ваша помощь, чтобы получить максимум от CAP_PRICE на основе определенных критериев в выберите заявлении SQL:Принимая Макс из колонки на основе определенных критериев
IF sid_rnk =0 and prd_id_rnk =1 and cap_price <> 0
then Max(cap_price) group by (sid_rnk,prd_rnk) as CAP1
Else if sid_rnk =0 and prd_id_rnk =2 and cap_price <> 0 and cap1 = 0
then Max(cap_price) group by (sid_rnk,prd_rnk) as cap2
Else if sid_rnk =0 and prd_id_rnk =3 and cap_price <> 0 and cap2 = 0
then Max(cap_price) group by (sid_rnk,prd_rnk) as cap3
Else if sid_rnk =1 and prd_id_rnk =1 and cap_price <> 0 and cap3 = 0
then Max(cap_price) group by (sid_rnk,prd_rnk) as cap4
Else if sid_rnk =1 and prd_id_rnk =2 and cap_price <> 0 and cap4 = 0
then Max(cap_price) group by (sid_rnk,prd_rnk) as cap5
Else if sid_rnk =1 and prd_id_rnk =3 and cap_price <> 0 and cap5 = 0
then Max(cap_price) group by (sid_rnk,prd_rnk)
Образец данных:
CREATE TABLE sap_prod
(
prd_id_rnk int,
sld_to_rnk int,
CAP_geo_1 varchar(20),
F_I_geo_2 varchar(20),
CAP_price int
)
INSERT INTO sap_prod
(prd_id_rnk, sld_to_rnk, CAP_geo_1, F_I_geo_2, CAP_price)
SELECT 1,0,'ASMO','ASMO',0 UNION ALL
SELECT 1,0,'ASMO','ASMO',0 UNION ALL
SELECT 1,0,'ASMO','ASMO',0 UNION ALL
SELECT 2,0,'WW' ,'ASMO',0 UNION ALL
SELECT 2,0,'WW' ,'ASMO',0 UNION ALL
SELECT 2,0,'WW' ,'ASMO',0 UNION ALL
SELECT 3,0,'EMEA','ASMO',0 UNION ALL
SELECT 3,0,'EMEA','ASMO',0 UNION ALL
SELECT 3,0,'IJKK','ASMO',0 UNION ALL
SELECT 3,0,'IJKK','ASMO',0 UNION ALL
SELECT 1,1,'ASMO','ASMO',0 UNION ALL
SELECT 1,1,'ASMO','ASMO',0 UNION ALL
SELECT 1,1,'ASMO','ASMO',0 UNION ALL
SELECT 2,1,'WW' ,'ASMO',0 UNION ALL
SELECT 2,1,'WW' ,'ASMO',0 UNION ALL
SELECT 2,1,'WW' ,'ASMO',0 UNION ALL
SELECT 3,1,'EMEA','ASMO',35 UNION ALL
SELECT 3,1,'EMEA','ASMO',40 UNION ALL
SELECT 3,1,'IJKK','ASMO',70 UNION ALL
SELECT 3,1,'IJKK','ASMO',50
результат должен быть: 70
Что такое sid_rnk в ваших критериях? –
И в чем разница с максимальным значением 'CAP_price'? – Lamak
@Lamak: Если какие-либо критерии удовлетворяют выше, он должен остановиться там. Например, если 2-я строка имеет CAP_PRICE как 5 .., она должна дать результат 5 – satyajit