PHP преобразовать список массивов строк в Array

Question

$str = 'answers[0] = "Love it"; answers[1] = "Hate it."; answers[2] = "Doesnt care"; answers[3] = "Like it";' 

Как преобразовать массив в массив?

Answer 1

$str = 'answers[0] = "Love it"; answers[1] = "Hate it."; answers[2] = "Doesnt care"; answers[3] = "Like it";'; 

preg_match_all('/"(.*)";/U', $str, $matches); 
$arr = $matches[1]; 

var_dump($arr); 

Answer 2

Что-то вроде этого?

<?php 
$str = '$answers[0] = "Love it"; $answers[1] = "Hate it."; $answers[2] = "Doesnt care"; $answers[3] = "Like it";'; 
eval($str); 
print_r($answers); 

?> 

Answer 3

Использование

preg_split

выбрать только значения и поместить его в массив,

пример:

$keywords = preg_split("/[\s,]+/", $str); 

Просто измените р attern!

проверка документации: http://php.net/manual/en/function.preg-split.php

Answer 4

$str = 'answers[0] = "Love it"; answers[1] = "Hate it."; answers[2] = "Doesnt care"; answers[3] = "Like it";'; 
$chunks = explode(';', $str); 

for ($aa=0;$aa<count($chunks);$aa++) 
{ 
    $chunks1 = explode('=', $chunks[$aa]); 
    $myArray[]=$chunks1[1]; 
} 

Answer 5

$str = 'answers[0] = "Love it"; answers[1] = "Hate it."; answers[2] = "Doesnt care"; answers[3] = "Like it";'; 

preg_match_all('/"(.*?)"/', $str, $answers); 

$answer = $answers[0]; 
print_r($answer); 

Answer 6

Если вы можете добавить новые строки после запятой (;), посмотрите на функцию parse_ini_string().

$str = str_replace(';', "\n", $str); // <- add them in the source if you can 
$array = parse_ini_string($str);