Широта и долгота - найти город и штат с помощью bigquery

Question

У меня есть широта и долгота в моей таблице. Я хочу найти ближайшее название города и штата, используя lat и long info, используя bigquery.

Answer 1

Надежда ниже быстрый пример даст вам хорошее направление, чтобы начать с

SELECT 
    yourLon, yourLat, ROUND(distance) AS distance, city, state 
FROM (
    SELECT 
    yourLon, yourLat, distance, city, state, 
    ROW_NUMBER() OVER (PARTITION BY yourLon, yourLat ORDER BY distance) AS win 
    FROM 
    JS((
    // input table 
    SELECT 
     points.yourLon AS yourLon, 
     points.yourLat AS yourLat, 
     cities.city AS city, 
     cities.state AS state, 
     cities.lon AS lon, 
     cities.lat AS lat 
    FROM (
     SELECT city, state, lon, lat FROM 
     (SELECT 'acampo' AS city, 'ca' AS state, -121.23200000000001 AS lon, 38.1964 AS lat), 
     (SELECT 'adelanto ' AS city, 'ca' AS state, -117.48 AS lon, 34.5894 AS lat), 
     (SELECT 'agoura hills ' AS city, 'ca' AS state, -118.76 AS lon, 34.1445 AS lat), 
     (SELECT 'alameda ' AS city, 'ca' AS state, -122.26 AS lon, 37.7606 AS lat), 
     (SELECT 'alamo ' AS city, 'ca' AS state, -122.019 AS lon, 37.8525 AS lat), 
     (SELECT 'albany ' AS city, 'ca' AS state, -122.294 AS lon, 37.8882 AS lat), 
     (SELECT 'albion ' AS city, 'ca' AS state, -123.705 AS lon, 39.2141 AS lat), 
     (SELECT 'alhambra ' AS city, 'ca' AS state, -118.12999999999998 AS lon, 34.0899 AS lat), 
     (SELECT 'aliso viejo ' AS city, 'ca' AS state, -117.736 AS lon, 33.5761 AS lat), 
     (SELECT 'altadena ' AS city, 'ca' AS state, -118.14000000000001 AS lon, 34.1884 AS lat), 
     (SELECT 'anaheim ' AS city, 'ca' AS state, -117.92667647058823 AS lon, 33.83603382352941 AS lat), 
     (SELECT 'anderson ' AS city, 'ca' AS state, -122.299 AS lon, 40.469 AS lat),  
     (SELECT 'angels camp ' AS city, 'ca' AS state, -120.625 AS lon, 38.0746 AS lat), 
     (SELECT 'antelope ' AS city, 'ca' AS state, -121.38099999999999 AS lon, 38.6861 AS lat), 
     (SELECT 'antioch ' AS city, 'ca' AS state, -121.806 AS lon, 37.99594999999999 AS lat), 
     (SELECT 'anza ' AS city, 'ca' AS state, -116.743 AS lon, 33.5886 AS lat), 
     (SELECT 'apple valley ' AS city, 'ca' AS state, -117.19333333333333 AS lon, 34.47484444444444 AS lat), 
     (SELECT 'aptos ' AS city, 'ca' AS state, -121.877 AS lon, 36.9926 AS lat), 
     (SELECT 'arbuckle ' AS city, 'ca' AS state, -122.015 AS lon, 39.0326 AS lat), 
     (SELECT 'arcadia ' AS city, 'ca' AS state, -118.04199999999999 AS lon, 34.1325 AS lat) 
    ) AS cities 
    CROSS JOIN (
     SELECT yourLon, yourLat FROM 
     (SELECT -122 AS yourLon, 38 AS yourLat), 
     (SELECT -117 AS yourLon, 34 AS yourLat), 
    ) AS points 
) , 
    // input columns 
    yourLon, yourLat, city, state, lon, lat, 
    // output schema 
    "[{name: 'yourLon', type: 'float'}, 
    {name: 'yourLat', type: 'float'}, 
    {name: 'city', type: 'string'}, 
    {name: 'state', type: 'string'}, 
    {name: 'distance', type: 'float'}]", 
    // function 
    "function(r, emit){ 
    var R = 3959; // Radius of the earth in miles 
    var dLat = deg2rad(r.lat-r.yourLat); 
    var dLon = deg2rad(r.lon-r.yourLon); 
    var a = Math.sin(dLat/2) * Math.sin(dLat/2) + 
     Math.cos(deg2rad(r.yourLat)) * Math.cos(deg2rad(r.lat)) * 
     Math.sin(dLon/2) * Math.sin(dLon/2); 
    var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a)); 
    emit({yourLon: r.yourLon, yourLat: r.yourLat, city: r.city, state: r.state, distance: R * c}); 

    function deg2rad(deg) { 
     return deg * (Math.PI/180) 
    } 
    }" 
) 
) 
WHERE win = 1 

результата, как показано ниже

yourLon yourLat distance city state  
-117.0 34.0 32.0  anza ca 
-122.0 38.0 10.0  alamo ca