данных JSON преобразовать в Java Object

Question

Это сообщение является в продолжении JPA : Not able to persist record due to incorrect values being passed from client to server

Когда я извлечения значений из вывода сервера JSON в следующем формате.

{"emp":[{"dept":{"deptNo":"10","dname":"ACCOUNTING","loc": 
    "NEW YORK"},"empno":"7934","ename":"MILLER","hiredate": 
    "1982-01-23T00:00:00+03:00","job":"CLERK","mgr":"7782","sal":"1300"}, 
    {"dept": 
    {"deptNo":"20","dname":"RESEARCH","loc":"DALLAS"},"empno":"7902","ename": 
    "FORD", 
    "hiredate":"1981-12-03T00:00:00+03:00","job":"ANALYST","mgr":"7566","sal": 
    "3000"},{"dept": 
    {"deptNo":"30","dname":"SALES","loc":"CHICAGO"},"empno":"7900","ename": 
    "JAMES", "hiredate": 
    "1981-12-03T00:00:00+03:00","job":"CLERK","mgr":"7698","sal":"950"}, 
    {"dept":{"deptNo":"20","dname":"RESEARCH","loc":"DALLAS"},"empno":"7876", 
    "ename": 
    "ADAMS","hiredate": 
    "1987-05-23T00:00:00+03:00","job":"CLERK","mgr":"7788","sal":"1100"}, 
    {"comm":"0","dept":  
    {"deptNo":"30","dname":"SALES","loc":"CHICAGO"},"empno":"7844","ename": 
    "TURNER","hiredate": 
    "1981-09-08T00:00:00+03:00","job":"SALESMAN","mgr":"7698","sal":"1500"}, 
    {"dept":{"deptNo":"10","dname":"ACCOUNTING","loc": 
    "NEW YORK"},"empno":"7839","ename":"KING","hiredate": 
    "1981-11-17T00:00:00+03:00","job":"PRESIDENT","sal":"5000"},   
    {"dept":"deptNo":"20","dname":"RESEARCH","loc":"DALLAS"},"empno":"7788", 
    "ename":"SCOTT","hiredate": 
    "1987-04-19T00:00:00+03:00","job":"ANALYST","mgr":"7566","sal":"3000"}, 
    {"dept":{"deptNo":"10","dname":"ACCOUNTING","loc": 
    "NEW YORK"},"empno":"7782","ename":"CLARK","hiredate": 
    "1981-06-09T00:00:00+03:00","job":"MANAGER","mgr":"7839","sal":"2450"}, 
    {"dept":"deptNo":"30","dname":"SALES","loc":"CHICAGO"},"empno":"7698", 
    "ename": 
    "BLAKE","hiredate": 
    "1981-05-01T00:00:00+03:00","job":"MANAGER","mgr":"7839","sal":"2850"}, 
    {"comm":"1400","dept": 
    {"deptNo":"30","dname":"SALES","loc":"CHICAGO"},"empno":"7654","ename": 
    "MARTIN","hiredate": 
    "1981-09-28T00:00:00+03:00","job":"SALESMAN","mgr":"7698","sal":"1250"}, 
    {"dept": 
    {"deptNo":"20","dname":"RESEARCH","loc":"DALLAS"},"empno":"7566","ename": 
    "JONES","hiredate": 
    "1981-04-02T00:00:00+03:00","job":"MANAGER","mgr":"7839","sal":"2975"}, 
    {"comm":"500","dept": 
    {"deptNo":"30","dname":"SALES","loc":"CHICAGO"},"empno":"7521","ename": 
    "WARD", "hiredate": 
    "1981-02-22T00:00:00+03:00","job":"SALESMAN","mgr":"7698","sal":"1250"}, 
    {"comm":"300","dept": 
    {"deptNo":"30","dname":"SALES","loc":"CHICAGO"},"empno":"7499", 
    "ename": 
    "ALLEN","hiredate":"1981-02-20T00:00:00+03:00","job":"SALESMAN","mgr": 
    "7698", 
    "sal":"1600"},{"dept": 
    {"deptNo":"20","dname":"RESEARCH","loc":"DALLAS"},"empno":"7369","ename": 
    "SMITH","hiredate": 
    "1980-12-17T00:00:00+03:00","job":"CLERK","mgr":"7902","sal":"800"}]} 

Если я хотел бы вставить данные в таблицу EMP, как ожидается, данные и как я могу передать, что данные от клиента JSON на сервер?

У меня есть следующий формат, но это не помогло.

function formToJSON() { 
     return JSON.stringify({ 
        "deptNo": "10", 
        "empno": "9004", 
        "ename": "JILL", 
        "job": "mfg", 
        "mgr": 34, 
        "sal": 456, 
        "comm": 900 
       }); 
      } 


$(document).ready(function() { 
       $("#btnSubmit").click(function() { 
        $.ajax({ 
         url: "Test1/rest/employee/", 
         type: "POST", 
         data: formToJSON(), 
         contentType: "application/json; charset=utf-8", 
         dataType: "json", 
         // console : 'ok', 
        }) 
       }); 
      }); 

Когда я отправляю из браузера, deptNo равно нулю, когда я получаю на сервере. Как ожидается на сервере?

Answer 1

На самом деле вы посылаете неверный формат JSON на сервере, поэтому вы получаете DeptNo = 0.

Правильный формат Json походит на это.

{ 
    "deptNo":{ 
      "deptNo":500, 
      "dname":"RESEARCH", 
      "loc":"DALLAS" 
     }, 
     "empno":7876, 
     "ename":"ADAMS", 
     "job":"1100", 
     "sal":"7788" 
    } 

Вы можете stringify ваш JSON, как показано ниже

function formToJSON() { 

    var test = { empno:7876, ename:'ADAMS', job:1100, sal:7788, 
       deptNo:{deptNo:6, dname:'RESEARCH', loc:'DALLAS'} 
       }; 

    return JSON.stringify(test); 

    } 

Продолжение поста JPA: Not able to persist record due to incorrect values being passed from client to server

имеет также эту проблему в формате JSON.