У меня есть хранимая процедура:Имея проблему вставив в базу данных
CREATE PROCEDURE busi_reg
(IN instruc VARCHAR(10),
IN tble VARCHAR(20),
IN busName VARCHAR(50), IN busCateg VARCHAR(100),
IN busType VARCHAR(50),
IN phne VARCHAR(20), IN addrs VARCHAR(200), IN cty VARCHAR(50),
IN prvnce VARCHAR(50), IN pstCde VARCHAR(10), IN nm VARCHAR(20),
IN surname VARCHAR(20), IN eml VARCHAR(50), IN pswd VARCHAR(20),
IN srce VARCHAR(50), IN refr VARCHAR(50), IN sess VARCHAR(50))
BEGIN
INSERT INTO b_register SET
business_name = busName,
business_category = busCateg,
business_type = busType,
phone = phne,
address = addrs,
city = cty,
province = prvnce,
postal_code = pstCde,
firstname = nm,
lastname = surname,
email = eml,
password = pswd,
source = srce,
ref_no = refr;
END;
Это мой PHP скрипт:
$busName = $_POST['bus_name'];
$busCateg = $_POST['bus_cat'];
$busType = $_POST['bus_type'];
$phne = $_POST['phone'];
$addrs = $_POST['address'];
$cty = $_POST['city'];
$prvnce = $_POST['province'];
$pstCde = $_POST['postCode'];
$nm = $_POST['name'];
$surname = $_POST['lname'];
$eml = $_POST['email'];
$srce = $_POST['source'];
$ref = $_POST['ref_no'];
$result2 = $db->query("CALL busi_reg('$instruc', '$tble', '$busName',
'$busCateg', '$busType', '$phne', '$addrs', '$cty', '$prvnce',
'$pstCde', '$nm', '$surname', '$eml', '$pswd', '$srce', '$refr', '')");
if($result)
{
echo "Data has been saved";
}
else
{
printf("Error: %s\n",$db->error);
}
Теперь ошибка, что я получаю:
**Commands out of sync; you can't run this command now**
Какой тип таблицы вы используете? –