program.exe перестает работать на большом входе

Question

вот мой код

#include<iostream> 
#include<map> 
#include<vector> 
#include<algorithm> 
#include<string> 
#include<math.h> 
#include<bitset> 
#include<cstring> 
#include<sstream> 
#include<iomanip> 
#include<queue> 
using namespace std; 
int d1[] = { 0,0,1,-1,1,-1 ,1,-1 }; 
int d2[] = { -1,1,0,0,1 ,-1,-1,1 }; 
string vec[200 + 5]; 
int counter = 0; 
long long int floodfill(int n1, int n2, char c1, char c2,int ss) 
{ 
    if (n1 < 0 || n1 >= ss || n2 < 0||n2>=vec[n1].length()) 
     return 0; 
    if (vec[n1][n2] != c1) return 0; 

    long long int ans = 1; 
    vec[n1][n2] = c2; 
    for (int i = 0; i < 8; i++) 
     ans = ans + floodfill(n1 + d2[i], n2 + d1[i], c1, c2,ss); 
    return ans; 
} 
int floodfill2(int n1, int n2, char c1, char c2,int ss) 
{ 
    if (n1 < 0 || n1 >= ss || n2 < 0 || n2 >= vec[n1].length()) 
     return 0; 
    if (vec[n1][n2] == '0') 
    { 
     floodfill(n1, n2, '0', c1,ss); 
     counter++; 
    } 
    if (vec[n1][n2] !=c1) return 0; 
    int ans = 1; 
    vec[n1][n2] = c2; 
    for (int i = 0; i < 4; i++) 
     ans = ans + floodfill2(n1 + d1[i], n2 + d2[i], c1, c2,ss); 
    return ans; 
} 
int main() { 
    int n1; 
    int n2; 
    int co = 1; 
    while (true) 
    { 
     cin >> n1; 
     cin >> n2; 
     if (n1 == 0 && n2 == 0) 
      break; 
     getchar(); 
     int aa = 0; 
     for (int i = 0; i < n1; i++) 
     { 
      char s[300]; 
      scanf("%s", s); 
      string g = ""; 
      int a = strlen(s); 
      for (int j = 0; j <a; j++) 
      { 
       string temp = ""; 
       if (s[j] == '0') 
        temp = "0000"; 
       else if (s[j] == '1') 
        temp = "0001"; 
       else if (s[j] == '2') 
        temp = "0010"; 
       else if (s[j] == '3') 
        temp = "0011"; 
       else if (s[j] == '4') 
        temp = "0100"; 
       else if (s[j] == '5') 
        temp = "0101"; 
       else if (s[j] == '6') 
        temp = "0110"; 
       else if (s[j] == '7') 
        temp = "0111"; 
       else if (s[j] == '8') 
        temp = "1000"; 
       else if (s[j] == '9') 
        temp = "1001"; 
       else if (s[j] == 'a') 
        temp = "1010"; 
       else if (s[j] == 'b') 
        temp = "1011"; 
       else if (s[j] == 'c') 
        temp = "1100"; 
       else if (s[j] == 'd') 
        temp = "1101"; 
       else if (s[j] == 'e') 
        temp = "1110"; 
       else if (s[j] == 'f') 
        temp = "1111"; 
       g =g+ temp; 
      } 
      vec[aa] = g; 
      aa++; 
     } 
     floodfill(0, 0, '0', '.',aa); 
     string ans = ""; 
     for (int i = 0; i < aa; i++) 
     { 
      for (int j = 0; j < vec[0].length(); j++) 
      { 
       counter = 0; 
       if (vec[i][j] == '1') 
       { 
        floodfill2(i, j, '1', '.',aa); 
        if (counter == 0) 
         ans = ans + 'W'; 
        else if (counter == 1) 
         ans = ans + 'A'; 
        else if (counter == 2) 
         ans = ans + 'K'; 
        else if (counter == 3) 
         ans = ans + 'J'; 
        else if (counter == 4) 
         ans = ans + 'S'; 
        else if (counter == 5) 
         ans = ans + 'D'; 
       } 
      } 
     } 
     sort(ans.begin(), ans.end()); 
     cout << "Case " << co << ": " << ans << endl; 
     co++; 

    } 
} 

он работает на этом входе

6 25 
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, но перестает работать на этом одном

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Answer 1

Вы должны это код:

string vec[200 + 5]; 
... 
if (vec[n1][n2] != c1) return 0; 

Я не могу видеть, что вы проверяете, что этот массив никогда не выходит за пределы то есть, что код пытается получить доступ к элементу больше, чем 205.

Я ожидаю, что с большим входом, вы выходите из облигаций.

Простым способом проверки является выполнение отладочной сборки. Порядочная библиотека времени выполнения отладки c должна давать вам явную ошибку за пределами границ.

В противном случае, вы можете добавить что-то вроде этого:

#define MAXSIZE 204 
string vec[ MAXSIZE]; 
... 
if(n1 >= MAXSIZE) 
{ 
    cout << "ERROR: Input too big\n"; 
    exit(1); 
}